can anyone please help me with this:
write an equation in slope intercept form that is perpecdicular to y= -5x+9
THANK YOU SOOOO MUCH IN ADVANCE! 10 POINTS TO THE BEST ANWSER!!! :)
write an equation in slope intercept form that is perpecdicular to y= -5x+9
THANK YOU SOOOO MUCH IN ADVANCE! 10 POINTS TO THE BEST ANWSER!!! :)
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Y = 1/5x + 9
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Slope is y=mx+b. Perpendicular lines have different slopes, but the same y intercept. Parallel lines have the same slope, but different y intercepts. So, if you want to write an equation that is perpendicular to this, you could do anything that has the y intercept as 9. So, some examples would be y=2x+9, -y=12x+9, y=58x+9, y=83295820395x+9. As long as the y intercept is 9, then the equation is perpendicular, just change the slope to something else.
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To find the new slope just use
m_new=-1/m_old
So for instance, if the old slope was 2/3, the new slope would be -3/2
You didn't give enough information to finish the problem, though. You need a point on the new line to finish the problem.
m_new=-1/m_old
So for instance, if the old slope was 2/3, the new slope would be -3/2
You didn't give enough information to finish the problem, though. You need a point on the new line to finish the problem.
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y= 5x + 9
slope is y=mx+b
you need the inverse of the slope so it should be 5.
slope is y=mx+b
you need the inverse of the slope so it should be 5.
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well i should know this considering i just had a test on this stuff 2 days ago, BUTTTT i am pretty certain i failed that test. so i don't know.
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Just read the examples from the text book, it shouldn't be that hard to figure out