Please show work or explain to me, i dont get how to solve it? Thank youuu!
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Make a common denominator. The top becomes (a^2-b^2)/ab and the bottom becomes (a+b)/b.
When you divide you flip the second fraction and multiply.
So... (a^2-b^2)*b/ab*(a+b).
a^2-b^2 = (a+b)(a-b) so the (a-b)s cancel out, as do the b's from b/ab.
So your final answer is (a-b)/a
When you divide you flip the second fraction and multiply.
So... (a^2-b^2)*b/ab*(a+b).
a^2-b^2 = (a+b)(a-b) so the (a-b)s cancel out, as do the b's from b/ab.
So your final answer is (a-b)/a
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((a/b) - (b/a)) / (1+ (a/b))
= [(a^2 - b^2)/ab] / [(a + b)/b]
= [(a - b)(a + b)/ab] / [(a + b)/b]
= (a - b)/a
or:
= 1 - b/a
= [(a^2 - b^2)/ab] / [(a + b)/b]
= [(a - b)(a + b)/ab] / [(a + b)/b]
= (a - b)/a
or:
= 1 - b/a
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((a/b) - (b/a))=(a^2-b^2)/(a*b) (1)
1+ (a/b)=(b+a)/b (2)
(1) & (2) [(a^2-b^2)*b]/[(a+b)*a*b]=(a-b)/a
1+ (a/b)=(b+a)/b (2)
(1) & (2) [(a^2-b^2)*b]/[(a+b)*a*b]=(a-b)/a