How do I solve 2p + 6 = 3p - 4

Go to algebra.com mostly explains all the sh*t you need

Get all P(s) to the same side. Try to get the variable to remain positive if at all possible. *When a number or variable changes sides they change from positive to negative(-) and vice versa

2p+6=3p-4

6=3p-4-2p

Then get all the numbers to the opposing side of the variable side

6+4=3p-2p

10=p

First you subtract 2p from each sides. You should end up with 6 = p - 4. Don't subtract 3p can cancel the positive 3p out and do it on the positive 2p. This will make it harder for you.Then you add 4 to cancel -4 out. Then you add 4 to the other side, so it's 10 = p

2p + 6 = 3p - 4
4 + 6 = 3p - 2p
10 = p

2p + 6= 3p-4
-2p -2p
6=p-4
+4 +4
p=10

2P+6=3P-4
-2P -2P
6=P-4
+4 +4
10=P

.

6+4=3p-2p ... then p= 10. solved.

P equals ten