Go to algebra.com mostly explains all the sh*t you need
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Get all P(s) to the same side. Try to get the variable to remain positive if at all possible. *When a number or variable changes sides they change from positive to negative(-) and vice versa
2p+6=3p-4
6=3p-4-2p
Then get all the numbers to the opposing side of the variable side
6+4=3p-2p
10=p
2p+6=3p-4
6=3p-4-2p
Then get all the numbers to the opposing side of the variable side
6+4=3p-2p
10=p
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First you subtract 2p from each sides. You should end up with 6 = p - 4. Don't subtract 3p can cancel the positive 3p out and do it on the positive 2p. This will make it harder for you.Then you add 4 to cancel -4 out. Then you add 4 to the other side, so it's 10 = p
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2p + 6 = 3p - 4
4 + 6 = 3p - 2p
10 = p
4 + 6 = 3p - 2p
10 = p
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2p + 6= 3p-4
-2p -2p
6=p-4
+4 +4
p=10
-2p -2p
6=p-4
+4 +4
p=10
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2P+6=3P-4
-2P -2P
6=P-4
+4 +4
10=P
-2P -2P
6=P-4
+4 +4
10=P
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.
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6+4=3p-2p ... then p= 10. solved.
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P equals ten