3 - 3√5
------------ (Division line)
√ 5
So it's: 3 minus 3 square roots of 5 all over the square root of 5.
If not, what do I do to simplify it? Thanks.
------------ (Division line)
√ 5
So it's: 3 minus 3 square roots of 5 all over the square root of 5.
If not, what do I do to simplify it? Thanks.
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no. You can't have a radical at the denominator. Multiply it by √5 on top and on bottom, like so
√5 times √5 equals 5
SO
3-3√5 / √5 is equal to 3-15 / 5 or -12/5
-12/5
√5 times √5 equals 5
SO
3-3√5 / √5 is equal to 3-15 / 5 or -12/5
-12/5
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No. It's generally improper to have radicals in the denominator of a fraction. You need to multiply by (root 5 / root 5) to fix it:
3 - 3root(5) (root 5) / (root 5)(root 5)
= 3root(5) - 3(5) / 5
= 3root(5) - 15 / 5
3 - 3root(5) (root 5) / (root 5)(root 5)
= 3root(5) - 3(5) / 5
= 3root(5) - 15 / 5
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rewrite it this way
multiply by 5^1/2 / 5^1/2
(3(5^.5) - 3*5) / 5 factor 3 out
3(5^.5 -5) /5
multiply by 5^1/2 / 5^1/2
(3(5^.5) - 3*5) / 5 factor 3 out
3(5^.5 -5) /5
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Why're you doing her homework instead?