Solve for x!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2^x+2=5^x-5

help!!!!

2^(x+2)=5^(x-5)
(x+2)log2 = (x-5)log5
(x+2)/(x-5) = log5/log2 = 2.3219
x+2 = 2.3219x - 11.6906
13.6906 = 1.3219x
x = 10.2955

2^(x + 2) = 5^(x - 5)
(x + 2) * ln(2) = (x - 5) * ln(5)
x * ln(2) + 2 * ln(2) = x * ln(5) - 5 * ln(5)
2 * ln(2) + 5 * ln(5) = x * ln(5) - x * ln(2)
(2 * ln(2) + 5 * ln(5)) = x * (ln(5) - ln(2))
x = (2 * ln(2) + 5 * ln(5)) / (ln(5) - ln(2))

Im assuming you mean (2^x)+2=(5^x)-5
2^x+2=5^x-5.
7=3^x
log 7=x
___3
log7/log3=x
x=1.771243

x is greater than or equal to negative nine million, your welcome!

x=69