There are 9 numbers in the basket. If I pick 3 numbers from the basket (dependent), what are the chances that these 3 numbers contain 6 and 9?
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9c3 = (9•8•7) / (1•2•3) = 84 ways to choose 3
7 ways to choose 6, 9, and 1 of the other 7, so
probability is 7/84 = 1/12
7 ways to choose 6, 9, and 1 of the other 7, so
probability is 7/84 = 1/12
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Depends on number range and also if you place back the number taken out or leave it out.