Math function help 10pts
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Math function help 10pts

[From: ] [author: ] [Date: 11-10-19] [Hit: ]
Note: You could also factorise giving 1/((x-1)(x+3)) OR (1/(x-1))*(1/(x+3))... theyre all the same.......
Given f(x)=x^2+2x-3, find f^-1(x). If u didnt know f^-1 is basically the inverse of f(x)

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replace x with y and vice versa.

thus:

x=y^2+2y-3

Add 3 to both sides:

x+3=y^2+2y

Complete the square for the right:

x+3 (+1)=y^2+2y+1=(y+1)^2

Square root both sides:

(x+4)^.5=y+1.

thus the inverse is:

-1+(x+4)^.5

QED

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f^-1(x) = 1/(x^2+2x-3)
The inverse of anything is just 1/anything.

Note: You could also factorise giving 1/((x-1)(x+3)) OR (1/(x-1))*(1/(x+3))... they're all the same.
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