I need help Solving for x and finding the zeros of f(x) (please help me)

Solving for x x^2 -3x = - 2

Find the zeros of f (x) = - 4(x-1)^2 + 4

x^2 - 3x = -2

Moving all values to the left side:

x^2 - 3x + 2 = 0

Factor:

(x - 2) * (x - 1) = 0

Solving, you get x = 1 and x = 2.


For the next:

-4(x - 1)^2 + 4 = 0

Expand:

-4(x^2 - 2x + 1) + 4 = 0

Factor out the -4:

-4 * ((x^2 - 2x + 1) - 1) = 0

x^2 - 2x = 0

x * (x - 2) = 0

Solving:

x = 0 and x = 2

Dear acressey1972,

x^(2)-3x=-2

To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side.
x^(2)-3x+2=0

For a polynomial of the form x^(2)+bx+c, find two factors of c (2) that add up to b (-3). In this problem -1*-2=2 and -1-2=-3, so insert -1 as the right hand term of one factor and -2 as the right-hand term of the other factor.
(x-1)(x-2)=0

Set each of the factors of the left-hand side of the equation equal to 0.
x-1=0_x-2=0

Since -1 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 1 to both sides.
x=1_x-2=0

Set each of the factors of the left-hand side of the equation equal to 0.
x=1_x-2=0

Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2 to both sides.
x=1_x=2

The complete solution is the set of the individual solutions.
x=1,2
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f(x)=-4(x-1)^(2)+4

To find the roots)/(zeros of the function, set the function equal to 0 and solve.
0=-4(x-1)^(2)+4

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
-4(x-1)^(2)+4=0

Factor out the GCF of -4 from each term in the polynomial.
-4((x-1)^(2))-4(-1)=0

Factor out the GCF of -4 from -4(x-1)^(2)+4.
-4((x-1)^(2)-1)=0