See the problem at:
http://www.flickr.com/photos/mrdmbob/
Thanks for your help!
http://www.flickr.com/photos/mrdmbob/
Thanks for your help!
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This will be hard to explain without pictures, but I'll give it a shot.
First find the radius (r):
(8+10)/2 = r
r = 18/2
r = 9
Then find the length of OP.
OP = r - 8
OP = 9 - 8
OP = 1
Let's call the point where the top of the dotted line intersects the curve of the circle 'Q'.
So now you have a triangle OPQ, and you know the length of OP = 1 and OQ = r = 9.
Now comes Pythagoras!
OP^2 + QP^2 = OQ^2
9^2 - 1^2 = QP^2
81 - 1 = QP^2
80 = QP^2
QP = sqrt(80)
QP = 8.9
So the length of the dotted line is approximate 8.9 (units).
First find the radius (r):
(8+10)/2 = r
r = 18/2
r = 9
Then find the length of OP.
OP = r - 8
OP = 9 - 8
OP = 1
Let's call the point where the top of the dotted line intersects the curve of the circle 'Q'.
So now you have a triangle OPQ, and you know the length of OP = 1 and OQ = r = 9.
Now comes Pythagoras!
OP^2 + QP^2 = OQ^2
9^2 - 1^2 = QP^2
81 - 1 = QP^2
80 = QP^2
QP = sqrt(80)
QP = 8.9
So the length of the dotted line is approximate 8.9 (units).