Please help with graphing y=(-11/2)x+9
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Please help with graphing y=(-11/2)x+9

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
y=9, plot point (0,9) call it pt.if x=2, y=-2, plot pt (2,......
Use the slope-intercept form to graph the following line.
y=(-11/2)x+9

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Draw x axis and y axis...Hope u know that
if x=0, y=9, plot point (0,9) call it pt. A
if x=2, y=-2, plot pt (2, -2) call it pt. B
if x= 1, y= -4.5 plot pt (1, -4.5) call it pt C.
draw a line passing pt. A, B. C. it will be a staight line
(actually only two pt are required, but we plot three to see we are right or wrong, if all three are in a straight line, we are write or otherwise wrong.

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STOP.

Ok, draw a table for x and y.

Compute, by your hand, the value of y for x from -2 to 2

Plot these points, physically, on a piece of paper in whatever plot paper you were forced to buy at the beginning of the year.

And link these points, with a pencil, with a straight line.

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ok that means that your line on the graph is going to pass the y axis at 9.
-11/2 means the line is going downwards 11 spaces and over to the right 2 spaces
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