3(x+7/3)^2= 1
-
3(x + 7/3)^2 = 1
(x + 7/3)^2 = 1/3
x + 7/3 = ± √(1/3)
x + 7/3 = ± 1 / √3
x + 7/3 = ± √3 / 3
x = (-7 ± √3) / 3
(x + 7/3)^2 = 1/3
x + 7/3 = ± √(1/3)
x + 7/3 = ± 1 / √3
x + 7/3 = ± √3 / 3
x = (-7 ± √3) / 3
-
(3x+7)^2=3;
9x^2+46+42x=0
9x^2+46+42x=0