Using log3(5) = x, which expression is equivalent to log9(0.6)? (first number beside log is the base)
A) 1/2 - x
B) 1/2 - x/2
C)2 - x
D) 2 - 2x
*The answer is B, but could someone explain to me how to get it?
A) 1/2 - x
B) 1/2 - x/2
C)2 - x
D) 2 - 2x
*The answer is B, but could someone explain to me how to get it?
-
y = log9(0.6)
= log9(3/5)
= log9(3) - log9(5)
[from logarithm law, logc(a/b) = logc(a) - logc(b)]
= log9(9^(1/2)) - log9(5)
[logc(a^b) = bloga, and loga(a) = 1]
= 1/2 - log9(5)
= 1/2 - (log3(5)/log3(9))
[change of base law, loga(b) = logc(b) / logc(a)]
= 1/2 - x/2
= log9(3/5)
= log9(3) - log9(5)
[from logarithm law, logc(a/b) = logc(a) - logc(b)]
= log9(9^(1/2)) - log9(5)
[logc(a^b) = bloga, and loga(a) = 1]
= 1/2 - log9(5)
= 1/2 - (log3(5)/log3(9))
[change of base law, loga(b) = logc(b) / logc(a)]
= 1/2 - x/2