Find f ' (x) for √5x-2

The square root sign should be over all of "5x-2." I keep getting 5/2√x , but this is wrong.
It's asking for the derivative. Please explain!

I'll choose best answer right away...thanks!

How are you getting 5/2 rt(x)?

Use the chain rule.

Write the equation in exponential form...

(5x-2)^1/2

Think of 5x-2 as its own unit, we'll call it unit u.

So first we need to get the derivative of u^1/2
1/2(u)^-1/2

Now we need to multiply this by the derivative of u
5 * 1/2(u)^-1/2

5/2 (u)^-1/2

Now replace u with what was in the parentheses:
5/2 (5x-2)^-1/2

chain rule f(x) = (5x - 2)^0.5
Derivitive = 0.5 x 5 x (5x -2 )^-0.5
use chain rule - with 5x - 2 as the inner function, multiplied by derivitive of this (5)