Basic Algebra Solve for X

Can someone help me solve for x in this equation.

.0611 = X^2 / (1768-X) (1332-X)

.0611 = x^2 / (1768-x)(1332-x)
.0611(1768-x)(1332-x) = x^2
.0611(2354976-1768x-1332x+x^2) = x^2
.0611(2354976-3100x+x^2) = x^2
143889.034-189.41x+.0611x^2 = x^2
.0611x^2-x^2-189.41x+143889.034 = 0
-.9389x^2-189.41x+143889.034 = 0
Use the quadratic equation or this site:
http://www.mathsisfun.com/quadratic-equa…
x=-505.1 or x=-303.4

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.0611 * (1788 - x ) * (1332 - x ) = x^2
(109.2468 - 0.0611x) * (1332 - x) = x^2
193,148.3424 - 109.2468x - 81.3852x + 0.0611x^2 - x^2 = 0
-0.9389x^2 - 190.632x + 193,148.324 = 0

Use the quadratic equation to solve for two possible values of x (since it's squared).
x = -566.30
x = -363.26


Whoever gave you that question must be an ***...

multiply both sides by ( 1768 -X) ( 1332 - X)

0.0611 ( 1768 - X) ( 1332- X) = X^2

0.0611 ( 2354976 - 1332X - 1768X + X^2) = X^2

143889.03 - 189.41X + 0.0611X^2 = X^2

0.9389X^2 + 189.41X - 143889.03 = 0

X = -505.129 OR 303.393 ANSWER

sqroot(.0611)(1768-x)(1332-x)=x
simplify it