could someone explain how you could quickly factorise this?
3x-2x^2>1
3x-2x^2>1
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I'm not sure how to do this quickly, but ...
3x - 2x > 1
-2x^2 + 3x - 1 > 0
-(2x - 1)(x - 1) > 0
(2x - 1)(x - 1) < 0
x < 1/2 or x > 1
3x - 2x > 1
-2x^2 + 3x - 1 > 0
-(2x - 1)(x - 1) > 0
(2x - 1)(x - 1) < 0
x < 1/2 or x > 1
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Use intmath.com