Unbeknownst to me is the process of binomial factorization. I have repeatedly attempted to derive the method for doing so via "practice problems," but to my dismay, I have not prevailed. If there be a gentleman (or lady) that could assist me, please disclose the operation! I will provide a problem and solution (as follows) for you to base your answer upon.
The situation which requires factorization:
(2x^2 + 5x)
The solution:
x(2x + 5)
P.S. I merely retrieved the answer to this particular conundrum from the omniscient back of the book.
The situation which requires factorization:
(2x^2 + 5x)
The solution:
x(2x + 5)
P.S. I merely retrieved the answer to this particular conundrum from the omniscient back of the book.
-
(2x^2 + 5x)
x(2x + 5)
It just works like that.
x(2x + 5)
It just works like that.
-
Ok, in the expression (2x^2+5x) has two terms: 2x^2 and 5x (terms are separated by operators, remember that). Then you look for factors common to each term (a common factor being defined as something that divides evenly into each term). In the case above, the only factor that 2x^2 and 5x have in common is x. 5x divided by x is 5, and 2x^2 divided by x is 2x (remember the rules for exponents?).
Now all that's left is to rewrite the equation as a product of its factors (meaning that you should be able to obtain the original equation by expansion). This leads to the equation x(2x+5)
Now all that's left is to rewrite the equation as a product of its factors (meaning that you should be able to obtain the original equation by expansion). This leads to the equation x(2x+5)
-
All you are doing here is factoring out the x, so taking the x out of all of the terms because then, if you think about how to multiply the the solution, you would distribute the x to each term. so if it was (2x^2 + 6x) you would take out 2x and make it 2x(x + 3), because 2x multiplied by x is 2x^2 and if you multiply x by 3 you get 6x. If you need more help feel free to send me a message and i will try to help as much as possible. Hope I Helped!