I am currently taking a pre-calculus class and my homework includes many f(x)-style problems. So far, I've been doing fine with them, however, these two are giving me a lot of trouble for some reason...
f (x) - x^2+1; f (x+2)
f (x) - x^2+1; f (x) +f (2)
My book provides the answers to both problems, but I cannot seem to achieve them on my own.
Any step-by-step help would be greatly appreciated!
Thank you in advance!
f (x) - x^2+1; f (x+2)
f (x) - x^2+1; f (x) +f (2)
My book provides the answers to both problems, but I cannot seem to achieve them on my own.
Any step-by-step help would be greatly appreciated!
Thank you in advance!
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Part one: replace x with x+2
(x+2)^2+1 = x^2+4x+4 +1 = x^2+4x+5
Part two: Re-write f(x) and add f(2)
{x^2+1}+{(2^2)+1} = {x^2+1}+5 = x^2+6
(x+2)^2+1 = x^2+4x+4 +1 = x^2+4x+5
Part two: Re-write f(x) and add f(2)
{x^2+1}+{(2^2)+1} = {x^2+1}+5 = x^2+6
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If f(x) = x^2 + 1, then f(x + 2) = (x + 2)^2 + 1 = x^2 + 4x + 4 + 1 = x^2 + 4x + 5
f(x) + f(2) = x^2 + 1 + 5 = x^2 + 6
f(x) + f(2) = x^2 + 1 + 5 = x^2 + 6
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not clear
what is f(x) = ? f(x ) = x^2+ 1? then f( x + 2) = ( {x + 2}^2 + 1
not sure what the notation means
what is f(x) = ? f(x ) = x^2+ 1? then f( x + 2) = ( {x + 2}^2 + 1
not sure what the notation means