Anyone good at math????
[From: ] [author: ] [Date: 11-08-19] [Hit: ]
Heres what you get when the factorization is complete(2x+1)(x-2)--------------------(3x+5)(x-2)Now, cancel the term (x-2) in the numerator and denominator and youll have this:-(2x+1)----------(3x+5)I assume the second problem is a true or false question, because the answer is false. The easiest way to check this is just to solve for x.x+1=0x=-1Now, substute that into the polynomial and see if you get 11.......
collect the divisors
x^2+2x-2
-
2x^2-3x-2
------------- (divided by) 1) I'd rearrange the numbers so they match up
10+x-3x^2
2x^2-3x-2
------------- (divided by) 2) 2x^2 divided by -3x^2 = cancel out the 2x^2 and -3x^2 turns into -1x^2 or
-3x^2+x+10 just -x^2 because you removed 2x^2's
-3x-2
------------- (divided by) 3) -3x divided by x = -3 because when you divided BY x you removed it
-x^2+x+10
-3-2
------------- (divided by) 4) Combine -3 and -2 to make -5
-x^2+10
-5
------------- (divided by) 5) -5 divided by 10 is like a fraction simplified to -1/2
-x^2+10
-1
------------- (divided by)
-x^2+2
Not sure if I did that right, it's been a while since I did that also. =/
-
Hi,
If you have been away from math for some time, you may need to review some before you understand what I will tell you. To do the first problem you need to factor the numerator and denominator into binomials. Here's what you get when the factorization is complete
(2x+1)(x-2)
-------------------
-(3x+5)(x-2)
Now, cancel the term (x-2) in the numerator and denominator and you'll have this:
-(2x+1)
----------
(3x+5)
I assume the second problem is a true or false question, because the answer is false.
The easiest way to check this is just to solve for x.
x+1=0
x=-1
Now, substute that into the polynomial and see if you get 11. Let's do that now by substituting -1 every place there is an x.
(-1)^3+3(-1)^2 -2
-1+3-2
=0
The remainder is zero, so the answer given is false, and x+1 is a factor the the polynoial that is given.
A long way of doing this is to use either long division or synthetic division. Since synthetic division is much shorter, let's do it that way. The dots are only to maintain spacing in this word processor.
__-1__|1....3...0...-2
,,,,,,,,,,,,,,,-1,,,-2...2
----------------------------------
...........1....2...-2..0
The zero in the third line indicates that the remainder is zero, not 11 and that x+1 is actually a factor of the polynomial. The other numbers are the polynomial that is left after the division. That is x^2 +2x-2.
You might want to review both synthetic division and long division of polynomials. It may be too late for the placement exam, but I hope this helps a little.
formeng
