What is 1/(2)(y) following the order of operations

What is the appropriate way to write 1/(2)(y) using the order of operations.

I understand 1/2y = y/2. I always thought 1/(2)(y) = y/2, however, someone else has told me otherwise claiming that since parenthesis's come before division that 1/(2)(y) should be viewed as 1/(2y). I am not convinced and wonder what other people think 1/(2)(y) is.

Simply put is
1/(2)(y) = y/2
or 1/(2)(y) = 1/(2y)

y/2
One divided by two is 1/2. Then you multiply that by y.

"someone else has told me otherwise claiming that since parenthesis's come before division that 1/(2)(y) should be viewed as 1/(2y)"

This is wrong.

Follow this rule I learnt in school recently:

The word is BODMAS so division comes before multiplication.

B = Brackets
O = Other (so powers, roots)
D = Division
M = Multiplication
A = Addition
S = Subtraction

I hope this helps you. :)

PE-MD-AS
Multiplication comes before division.

1/(2)(y)
1/2y

Multiplication in fact does NOT come before division just like addition does not come before subtraction.
1/(2)(y) = y/2