HELP i'm stuck with my maths homework :/

So nth term..

the question is " The nth term of a sequence is given by each of the rules below. Use this to write down the first 6 terms of each sequence:

A. 6n-2
B. 10n+3
C. 4n+1
D. 8n-3

Thanks :) xx

I'll do one for you and you'll easily see how to do the rest.
The nth term just means the "first, second, third, fourth, etc"

So all you have to do to find the first term is to plug "1" into the letter n.
For the second term, plug "2" into the letter n.

So for A.
The first term is (6)*(1)-2 =4
The second term is (6)*(2)-2 = 10
The third term is (6)*(3)-2 = 16
The fourth term is (6)*(4)-2 = 22
The fifth term is (6)*(5)-2 = 28
The sixth term is (6)*(6)-2 = 34

So the first six terms of A. are: (4, 10, 16, 22, 28, 34)

You can also get this by simply finding the first term and then adding 6 each time for A. For B, you can replace the numbers as above, or just find the first term and add 10 each time for B. (In the sequence, the -2, +3, +1, -3 are the constants meaning that they won't change with whatever you put in for "N" - the numbers in front of N, though, tell you how much to add each time to get the next term.)

Just plug in each number, 1 through 6, in for n and simplify. For example:

A. 6(1) - 2 = 4
6(2) - 2 = 10
6(3) - 2 = 16
6(4) - 2 = 22
6(5) - 2 = 28
6(6) - 2 = 34.

So the first 6 terms for A are 4, 10, 16, 22, 28, 34. The others are the exactly the same.

A. 4, 10, 16, 22, 28, 34
B. 13, 23, 33, 43, 53, 63
C. 5, 9, 13, 17, 21, 25
D. 5, 13, 21, 29, 37, 45

Qu__Expression__1___2____3____4____5___ 6
1_____6n - 2____ 4___10___16___22___28___34
2_____10n + 3___13__23___33___43___53___63
3_____4n + 1____5___ 9____13___17___21___25
4_____8n - 3____ 5___13___21___29___37___45