So the question is the following system of equations has ______ possible solution(s):
A.0
B.1
C. 2
D. infinite
The sytem of equations are: 3x-2y=6 and y=-3/2x-2
Please show your steps, I'm so confused. Haha.
A.0
B.1
C. 2
D. infinite
The sytem of equations are: 3x-2y=6 and y=-3/2x-2
Please show your steps, I'm so confused. Haha.
-
Put 3x-2y=6 into proper slope-intercept form
-2y = -3x + 6
2y = 3x-6 (I mult. both sides by -1
y = 3/2(x) -3
Now compare this equation to y = -3/2(x) -2
The slopes are NOT the same [3/2 and -3/2]
Therefore these lines (that's what they are because they're both linear) intersect at one point.
The answer is B
-2y = -3x + 6
2y = 3x-6 (I mult. both sides by -1
y = 3/2(x) -3
Now compare this equation to y = -3/2(x) -2
The slopes are NOT the same [3/2 and -3/2]
Therefore these lines (that's what they are because they're both linear) intersect at one point.
The answer is B