The captain of a freighter 6 km from the nearer of two unloading docks on the shore finds that the angle

the captain of a freighter 6 km from the nearer of two unloading docks on the shore finds that the angle between the lines of sight to the two docks is 35 degrees. if the docks are 10 km apart, how far is the tanker from the farther dock.


please help math final tomorrow!!!

Hello

find the angle opposite to the ship-second dock- connection. Find first the angle opposite to the 6 km connection to the first dock, using the sine law.

sine(angle)/6 = sin35/10
sine (angle) = 6sin35/10 = 0.344 -->
angle = 20.12966°
And the angle opposite to the distance ship-second dock is = 180 - 35 - 20.12966 = 124.870°.

Now use sine law again to find distance x (ship-second dock)
x/sin124.870 = 10/sin35
x = 10sin124.870/sin35 = 14.304 km.

Regards