Eliminate the parameter and find a corresponding rectangular equation. X=2t+1 Y=t^2-2

A) y=1/4(x+1)^2-2
B) y=1/4(x-1)^2-2
C) y=1/4(x+1)^2+2
D) y=1/4(x-1)^2+2

Please help thank you quick!

Start out by solving x = 2t + 1 for t to get:
x = 2t + 1 ==> t = (x - 1)/2.

Substituting this into y = t^2 - 2 yields:
y = [(x - 1)/2]^2 - 2 = (1/4)(x - 1)^2 - 2.

Therefore, the answer is (B).

I hope this helps!