1. What is the equation in the form of y=mx+ b of the line (0,2) , (1,7).
2. What is the equation in the form of y=mx+ b of the line (0,3) , (5,-3).
2. What is the equation in the form of y=mx+ b of the line (0,3) , (5,-3).
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m is the slope & m = difference in y's/difference in x's. Make sure that if you put the y from one point first, you also put the x from that same point first, or else your sign will be wrong. After you get m, plug either of the points in to solve for b.
1. m = (7 - 2)/(1 - 0) = 5/1 = 1 [notice I had the 7 first for the y's, so I put 1 first for x's)
Now put that m in the equation & use either of the points to solve for b.
y = 5x + b
7 = 5*1 + b
b = 7 - 5 = 2
Your equation is y = 5x + 2
2.
m = (3 - -3)/0 - 5) = (3 + 3)/(0 - 5) = 6/(-5) = -6/5
y = -6/5x + b
3 = -6/5*0 + b
b = 3
Your equation is y = -6/5x + 3
1. m = (7 - 2)/(1 - 0) = 5/1 = 1 [notice I had the 7 first for the y's, so I put 1 first for x's)
Now put that m in the equation & use either of the points to solve for b.
y = 5x + b
7 = 5*1 + b
b = 7 - 5 = 2
Your equation is y = 5x + 2
2.
m = (3 - -3)/0 - 5) = (3 + 3)/(0 - 5) = 6/(-5) = -6/5
y = -6/5x + b
3 = -6/5*0 + b
b = 3
Your equation is y = -6/5x + 3
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a] calculate the slope between the points
b] take one of the points and substitute its x and y values, and the slope, into the generic equation y = mx + b, leaving b as b, while you have numbers for x, y, and m.
c] solve for b
d] write the equation y = mx + b not substituting for x and y, but plugging in the values for m and b
b] take one of the points and substitute its x and y values, and the slope, into the generic equation y = mx + b, leaving b as b, while you have numbers for x, y, and m.
c] solve for b
d] write the equation y = mx + b not substituting for x and y, but plugging in the values for m and b
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What is the equation in the form of y=mx+ b of the line (0,2) , (1,7).
m=7-2/1-0 = 5/1 =5
(y-y1)=m(x-x1)
(y-2)=5(x-0)
y-2 =5x
y=5x+2
2. What is the equation in the form of y=mx+ b of the line (0,3) , (5,-3).
m=-3-3/5-0
m=-6/5
y-3 =-6/5 (x-0)
y- 3 = - 6/5 x
y= -6/5x +3
5y = -6x +15
m=7-2/1-0 = 5/1 =5
(y-y1)=m(x-x1)
(y-2)=5(x-0)
y-2 =5x
y=5x+2
2. What is the equation in the form of y=mx+ b of the line (0,3) , (5,-3).
m=-3-3/5-0
m=-6/5
y-3 =-6/5 (x-0)
y- 3 = - 6/5 x
y= -6/5x +3
5y = -6x +15
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1) (0,2) , (1,7) m= 7-2/1-0 =5. Let (x,y) be the other point on this line.
(y-2)/(x-0)=5. By equating this y=5x+2.
2) (0,3) ,(5,-3) m=-3-3/5-0 = -6/5. Let (x,y) be the point on this line.
(y-3)/(x-0)=-6/5. By equating this 5y=-6x+15 i.e. y=-6/5+3.
(y-2)/(x-0)=5. By equating this y=5x+2.
2) (0,3) ,(5,-3) m=-3-3/5-0 = -6/5. Let (x,y) be the point on this line.
(y-3)/(x-0)=-6/5. By equating this 5y=-6x+15 i.e. y=-6/5+3.
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Graph the two points make a line, where it crosses the y axis that's the y intercept ( or b) , and then find the slope. I guess you can use the slope formula y1 -y2 over x1 -x2 and that'ss m, y and x stay there.
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1. The equation is y = 5x + 2 .
2. 6x - 5y + 15 = 0 . [y = (6/5)x + 3 .]
2. 6x - 5y + 15 = 0 . [y = (6/5)x + 3 .]
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Read this you will get by yourself how to find slope, it's easy;
http://en.wikipedia.org/wiki/Slope
http://www.purplemath.com/modules/strtln…
http://en.wikipedia.org/wiki/Slope
http://www.purplemath.com/modules/strtln…