The width of a rectangle is (2x − 4)
in. The length of the rectangle is three times the width. Find the area of the rectangle in terms of the variable x.
3(2x-4) did i set it up right?
in. The length of the rectangle is three times the width. Find the area of the rectangle in terms of the variable x.
3(2x-4) did i set it up right?
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yep...
the width will be 3(2x - 4)
so the area will be (2x-4) * (6x-12)
ie, 12*x*x - 24x - 24x + 48
ie, 12*x*x - 48x +48
the width will be 3(2x - 4)
so the area will be (2x-4) * (6x-12)
ie, 12*x*x - 24x - 24x + 48
ie, 12*x*x - 48x +48
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No, you didn't set it up right.
Width = (2x-4)
Length = 3(2x-4)
Area = Width * Length = 3 (2x-4) (2x-4)
Width = (2x-4)
Length = 3(2x-4)
Area = Width * Length = 3 (2x-4) (2x-4)
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area of the rectangle = w * l
so the length is must be 3(2x-4)
area of the rectangle = (2x-4) * 3(2x-4)
u can get the answer..
so the length is must be 3(2x-4)
area of the rectangle = (2x-4) * 3(2x-4)
u can get the answer..
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3x(2x-4)
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Yep!