Easy two-part question. I just want to be sure I have the correct workthrough/answer. Plese tell me why you selected what you selected for the center/vertex numbers and the base solutions that you used to solve for it. Thank you.
Find the center and vertex of the following ellipse: (x^2 / 169) + (y^2 / 144) = 1
Find the center and vertex of the following ellipse: ((x - 6)^2 / 4) + ((y + 7)^2 / 16) = 1
Find the center and vertex of the following ellipse: (x^2 / 169) + (y^2 / 144) = 1
Find the center and vertex of the following ellipse: ((x - 6)^2 / 4) + ((y + 7)^2 / 16) = 1
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Both equations are in standard form, which should make this simple.
The first equation's graph is an ellipse with center at (0,0). Since 169 is more than 144, the ellipse stretches longer horizontally than it does vertically (that is, the major axis is horizontal). So, the vertices are (13,0) and (-13,0).
The second equation's graph is an ellipse with center (6, -7). Since 16 is more than 4, the major axis is vertical; we should move up or down 4 units from the center to get to the vertices. So, the vertices are (6, -11) and (6, -3).
The first equation's graph is an ellipse with center at (0,0). Since 169 is more than 144, the ellipse stretches longer horizontally than it does vertically (that is, the major axis is horizontal). So, the vertices are (13,0) and (-13,0).
The second equation's graph is an ellipse with center (6, -7). Since 16 is more than 4, the major axis is vertical; we should move up or down 4 units from the center to get to the vertices. So, the vertices are (6, -11) and (6, -3).