Whats this answer to this problem its word problems algebra

can you please answer theses problems please. 1st, find three consecutive odd integers such that the same of the smallest and 4 times the largest is 61 . next juan is 8 years older than his sister in 3 year he will be twice as old as she will be the how old are they now. next, c and y candy company mixes candy that cost $6.00 per kg with candy that costs $ 4.50 per kg how many killograms of each are needed to make a 3kg bag that cost $15.00 last problem im sorry im asking for much but its for a test and if i pass it i move onto geometry. how much water must be added to a 12 grams of a 90% iodine solution to produce a 25% iodine solution. thanks if you can anser that will be great if this is too much plz leave your answers but showing work will help me more

1)
Consider 3 odd integers to be 2n+1, 2n+3, 2n+5
sum of the smallest and 4 times largest is 61 so, smallest is 2n+1 largest is 2n+5
hence, 2n+1+4(2n+5)=61
this gives, 2n+1+8n+20=61
thus 10n=61-1-20
10n=40
n=4
so consecutive numbers are:
(2*4)+1=9
(2*4)=3=11
(2*4)+5=13

2)
let juan's present age be X and sister's present age be Y
juan is 8 years older than sister, so X=Y+8------------ equation 1
in three years he will be twice as old as her, so u get the equation
X+2 = 2(Y+2)---------------equation 2
substituting equation 1 in equation 2 we get.....
Y+10=2Y+4
thus Y=6
substituting Y in equation 1 we get... X=14

3)
Let weight for $6.00 candy be X
let weight for $4.50 candy be Y
now total cost is equal to their weights * induvidual cost!!
ie, cost incurred due to $6.00 per kg candy is 6*X
cost incurred due to $4.50 per kg candy is 4.5*Y
so total cost is $15 hence
6*X + 4.5*Y=15
total weight is 3Kg
so X+Y=3
6X+4.5Y=15
X+Y=3
solving we get
X=1 and Y=2 ie weight of $6.00 is 1 and other weight is 2Kg

4)
12 gms of 90%iodine solution will have:
12*90/100 =10.8 gmsof iodine