Solving logarithm problems
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Solving logarithm problems

[From: ] [author: ] [Date: 11-05-24] [Hit: ]
.4.Because we now have an equal base (4), the exponents are equal as well.........
16^(4x-2)=1/64

I need help with this problem...:(

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16^(4x-2)=1/64
..|________|____Obtain a common base. A common base could be ....4.

16 = 4^(2) and 1/64 = 4^(-3)


4^(2(4x-2)) = 4^(-3)

Because we now have an equal base (4), the exponents are equal as well...

2(4x-2) = -3

8x - 4 = -3

8x = 1

x = 1/8

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16^(4x-2)=1/64
(2^4)^(4x-2) = 2^-6
2^(16x-8) = 2^-6
16x -8 = -6
16 x = 2
x = 2/16 = 1/8
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