16^(4x-2)=1/64
I need help with this problem...:(
I need help with this problem...:(
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16^(4x-2)=1/64
..|________|____Obtain a common base. A common base could be ....4.
16 = 4^(2) and 1/64 = 4^(-3)
4^(2(4x-2)) = 4^(-3)
Because we now have an equal base (4), the exponents are equal as well...
2(4x-2) = -3
8x - 4 = -3
8x = 1
x = 1/8
..|________|____Obtain a common base. A common base could be ....4.
16 = 4^(2) and 1/64 = 4^(-3)
4^(2(4x-2)) = 4^(-3)
Because we now have an equal base (4), the exponents are equal as well...
2(4x-2) = -3
8x - 4 = -3
8x = 1
x = 1/8
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16^(4x-2)=1/64
(2^4)^(4x-2) = 2^-6
2^(16x-8) = 2^-6
16x -8 = -6
16 x = 2
x = 2/16 = 1/8
(2^4)^(4x-2) = 2^-6
2^(16x-8) = 2^-6
16x -8 = -6
16 x = 2
x = 2/16 = 1/8