Whats this answer to this problem its word problems algebra
[From: ] [author: ] [Date: 11-05-24] [Hit: ]
this whole thing is an entire worksheet that you just dont want to do-a , a+2 , a + 4a + 4a + 16 = 615a = 45a = 99 , 11 , 13-1. First,......
amount of water to be added be X
10.8/(10.8+X)*100 =25
total solute /solvent *100 is the formula
cross multiplying we get
1080= 25X+270
1080-270 =25X
810=25X
hence X=32.4
so water to be added is 32.4
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how about you just do your homework instead of having people do it for you over the internet. this whole thing is an entire worksheet that you just dont want to do
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a , a+2 , a + 4
a + 4a + 16 = 61
5a = 45
a = 9
9 , 11 , 13
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1. First, set up the equations. x is the largest integer and y is the smallest. y + 4x=61 and x-4=y. replace y with x-4 so you have only one variable and solve. x=13 and y=9 so the integers are 9, 11, and 13.
2. Again, set up the equations with what you know. x is Juan's age and y is his sisters. x=8 + y and x+3=2y. substitute x in for the second equation so you have y+11=2y. y=11 and x=19 so his sister is 11 and he is 19.
3. Again, set up the equations with what you know. x is the kg of $6 candy and y is the kg of $4.5 candy. x+y=3kg and 6x+4.5y=$15. solve the first equation for either variable (i'll do y) so you get x=3-y. substitute this in for the second equation so you have 6(3-y)+4.5y=15. distribute so you have 18-6y+4.5y=15. simplify to get 3=1.5y. y=2kg and x=1kg so you have 2 kg of the $4.5 candy and 1kg of the $6 candy.
4. A 90% iodine solution made from 12g of Iodine will be in 13.33( mL, although i'm not 100% sure) of solution (water). To find how much water is in a 25% solution, take the (12g/xmL)(100%)=25% where x is mL of solution. when you solve for x you get 48 mL of solution. 48-13.33(the original amount of solution)=34.67mL of solution added.
Hope this helped, and good luck on your test!
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