Use the quadratic forumla to solve. 0.7x^2=4.2x+0.7
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Use the quadratic forumla to solve. 0.7x^2=4.2x+0.7

[From: ] [author: ] [Date: 11-05-20] [Hit: ]
7x² - 4.2x - 0.Note that we can factor that expression by 0.0.Here, by ax² + bx + c = 0,......
0.7x^2=4.2x+0.7
The answers I'm getting are some reallllly big decimals so I don't think I'm doing it right. Help please?

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Rearrange the terms to get:

0.7x² - 4.2x - 0.7 = 0

Note that we can factor that expression by 0.7 to get:

0.7(x² - 6x - 1) = 0

Here, by ax² + bx + c = 0, neglecting 0.7, a = 1, b = -6 and c = -1. Then, by quadratic formula:

x = (-b ± √(b² - 4ac))/2a
= (6 ± √((-6)² - 4*1*-1))/2
= (6 ± √(36 + 4))/2
= (6 ± √40)/2
= (6 ± √(4*10))/2
= (6 ± 2√10)/2
= 2(3 ± √10)/2
= 3 ± √10

I hope this helps!
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