Solve for 4c²-9=0? 20 characters

thanks

Difference of squares
4c^2 - 9 = 0
(2c + 3)(2c - 3) = 0
So if 2c + 3 = 0 then c = -3/2
And if 2c - 3 = 0 then c = 3/2
S = {-3/2, 3/2}

4c²-9=0
is a difference of two squares, so it factors as
(2c + 3)(2c - 3) = 0
which has the two solutions
c = 3/2 and c = -3/2

4c^2 - 9 = 0
(2c + 3)(2c - 3) = 0

c = {-3/2, 3/2}

or

4c^2 - 9 = 0
4c^2 = 9
c^2 = 9/4
c = ± √(9/4)
c = ± 3/2

4c²-9=0

c = 3/2, -3/2

4c^ = 9
c^ = 9 /4
c = 3/2
or 1.5

use quadratic equation then you see
c = +/- 3/2

answer is 2.25 cause you move the nine to wear 0 is then divide 9/4 hope i helped