Does 6/2 (1+2) equal 9 or 1

The answer is 9, and yes you do use PEMDAS. first add the parentheses (2+1) which equals 3. Then everything else goes 6/2*3=9. you dont multiply 2*3 because the 2 and 3 arent in parentheses with each other and there for arent both in the denominator. the 3 is actually in the numerator. If it were 6/[2(1+2)] it would equal 1.

Really? People that say it equals 1 defy the order of operations.

Order of operations is PEMDAS, or Paranthesis, Exponents, Multiplication, Division, Addition, Subtraction.

1. Paranthesis
2. Exponents
3. Multiplication AND division (here is where people are messing up, they are the same rank, you don't do one and then the other, you do whatever comes first)
4. Addition AND subtraction (same rank as well)

In short, you would calculate it like this:
6/2(1+2)

1+2 = 3

6/2(3)

6/2 = 3, YOU DO THIS FIRST, because it goes LEFT TO RIGHT. You do NOT do 2*3 first, because 6/2 is a division, and since multiplication and division are the same rank, and it goes LEFT TO RIGHT, that means it would be done first, not 2*3.

So, it would be 3(3) = 9.

There you go.

It's 1.
Basically because when 6÷2(1+2) you do the brackets first. So it's 6÷2(3). But it's only the 2 that is multiplied by 3, not the entire expression. You get 9 when you go 6÷2 is 3 and then x 3 is 9.
If we had x's for example, this is easier to see. 6÷x(1+2), when you solve this it becomes 6÷x+2x, which is 6÷3x. When x is 2, as in the original equation, 6÷(3x2), the answer is shown to be 1. To get nine from this, you have expanded 6÷x(1+2) as 6÷x(3), and then solved it by dividing 6 by x and multiplying the whole thing by 3 to get (6÷2)(3), which is absurd. You need to leave the brackets on the 3, and this means the multiplication is done first.You can't just reassign the 3 to be multiplied with the whole thing instead of just the 2.