If y = 2sin π - 5cos θ, then dy/dθ =

y = 2sin π - 5cos θ
dy/dθ = 5 sin(θ)

I am assuming that the expression is:

y = 2sin(πθ) - 5cos(θ)

Note that d/dx sin(f(x)) = f'(x)cos(f(x)) and d/dx cos(f(x)) = -f(x)sin(f(x)), so:

dy/dθ = 2πcos(πθ) + 5sin(θ)

I hope this helps!