10 POINTS EASIEST MATH Q EVER

1. a gumball machines conatins 6 yellow gumballs and five orange gumballs. what is the probability at random and without replacement of obtaining two yellow gumballs? please shoiw me how
2.the probability that tim will be elected as class president is .7 what is the probabilty that he won't be elected as class president? show work please.
3.a fair die and fair coin are tossed find p( h, odd#) anf find p (t, number >4)

Question 1.)

Total number of gumballs: 11

yellow: 6 orange:5

P[get two yellow gumballs] = (6/11) * (5/10) = 30/110 = 3/11


[The reason for the 5/10 has to do with that after you pick the first yellow gumball the number of yellow gumballs decreases by one (from 6 to 5) also once you going to pick a second gumball the number of total gumballs to choose from decreases by 1 (from 11 to 10). This is because we are choosing gumballs "without replacement".

Question # 2

Let E be the event that Tim is elected.

P(E) = 0.7

Using the complement rule

P(E') = 1 - P(E)

P(E') = 0.3 [This is the probability that Tim is not elected]

Question 3.)

a.) Find the probability that you get heads and a odd number

Sample Space for Coin {Heads,Tails}

Sample Space for die {1,2,3,4,5,6}

P[Get an odd number] = 3/6 = 1/2

P[Get Heads] = 1/2

P[Get odd number and heads] = (3/6) * (1/2) = (1/2) * (1/2) = 1/4

b.) Probability you get tails and a number greater than 4

I will let you do this one...