In the figure bellow C1= 1 F, C2 = 4 F, C3 = 1 F and the capacitors are fully charged. If the charge across C1 is 4 C, what is the charge across C2?
In the Figure bellow E= +2 V, C1=C2= 2 F, C3 = 1 F and the capacitors are fully charged. What is the total charge across C3?
In the figure bellow E = +2 V, C1=C2=C3=1 F and the capacitors are fully charged. What is the total charge in the circuit?
They are all looking at the same circuit but I am having trouble with the concept of finding the charge. Best answer will provide answers and a concept explanation
FIGURE
http://i48.tinypic.com/a3toj.png
In the Figure bellow E= +2 V, C1=C2= 2 F, C3 = 1 F and the capacitors are fully charged. What is the total charge across C3?
In the figure bellow E = +2 V, C1=C2=C3=1 F and the capacitors are fully charged. What is the total charge in the circuit?
They are all looking at the same circuit but I am having trouble with the concept of finding the charge. Best answer will provide answers and a concept explanation
FIGURE
http://i48.tinypic.com/a3toj.png
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Charge on C1 and C2 is identical as they are in series.
The series equivalent of C1 and C2 is 1•4/5 = 0.8 F
Voltage across the pair is
V = Q/C = 4/0.8 = 5 volts, and that is the voltage across C2 also
Charge ON C2 (not across) is Q = CV = 5x4 = 20C
2) Q = CV = 1F x 2v = 2C
Charge is ON, not across.
3) The two in series are equivalent to 0.5F, and the charge is Q = CV = 2x0.5 = 1C, and that same charge is on both caps.
The charge on C3 is Q = CV = 1x2 = 2C. Total charge is 3C
PS, these have nothing to do with Thevenin equivalents.
The series equivalent of C1 and C2 is 1•4/5 = 0.8 F
Voltage across the pair is
V = Q/C = 4/0.8 = 5 volts, and that is the voltage across C2 also
Charge ON C2 (not across) is Q = CV = 5x4 = 20C
2) Q = CV = 1F x 2v = 2C
Charge is ON, not across.
3) The two in series are equivalent to 0.5F, and the charge is Q = CV = 2x0.5 = 1C, and that same charge is on both caps.
The charge on C3 is Q = CV = 1x2 = 2C. Total charge is 3C
PS, these have nothing to do with Thevenin equivalents.