An empty parallel plate capacitor is connected between the terminals of a 13.3-V battery and charges up. The capacitor is then disconnected from the battery, and the spacing between the capacitor plates is doubled. As a result of this change, what is the new voltage between the plates of the capacitor?
A: __________ V
A: __________ V
-
Q = CV
Q = 13.3C
now the capacitance reduces to half and the charge remains the same so
13.3C = XC/2
X = 26.6 V
Q = 13.3C
now the capacitance reduces to half and the charge remains the same so
13.3C = XC/2
X = 26.6 V
-
AUDIOFORUM.NET
WEBSITEFORUM.NET
CLICKBANKFORUM.NET
TOYSFORUM.NET
GADGETFORUM.NET
FORUMBOARDS.NET
VERYSOON.NET
MAKEMONEYONLINEWAYS.NET
CLICKBANKS.NET
CLICKBANKAFFILIATES.NET
WHATISSIGN.COM
WHATISAIR.NET
WHATISBUSINESS.NET
WHATISWEBSITE.NET
WHATISWEB.NET
WHATISSITE.NET
HIDEMYMOTHER.COM
HIDEMYFATHER.COM
HACKMYIP.COM
MIKESS.COM
VERYSOON.NET
WEEKISSUES.COM
GOLDENBOOKMARKS.COM
TANDIONO.COM
WEBSITEFORUM.NET
CLICKBANKFORUM.NET
TOYSFORUM.NET
GADGETFORUM.NET
FORUMBOARDS.NET
VERYSOON.NET
MAKEMONEYONLINEWAYS.NET
CLICKBANKS.NET
CLICKBANKAFFILIATES.NET
WHATISSIGN.COM
WHATISAIR.NET
WHATISBUSINESS.NET
WHATISWEBSITE.NET
WHATISWEB.NET
WHATISSITE.NET
HIDEMYMOTHER.COM
HIDEMYFATHER.COM
HACKMYIP.COM
MIKESS.COM
VERYSOON.NET
WEEKISSUES.COM
GOLDENBOOKMARKS.COM
TANDIONO.COM