The electric potential energy stored in the capacitor of a defibrillator is 86 J, and the capacitance is 110 μF. What is the potential difference across the capacitor plates?
A: __________ V
A: __________ V
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E = 0.5*C*V^2
V = sqrt(2*E/C) = sqrt(2*86 / 110*10^-6) = 1250 V
V = sqrt(2*E/C) = sqrt(2*86 / 110*10^-6) = 1250 V