Determine the periodic time
The maximum angular velocity
The maximum angular velocity
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The periodic time of a simple pendulum in low-amplitude oscillation is T = 2π√(L/g) where L is the length and g the gravitational acceleration
Hence: T = 2.π.√(0.9/9.81) = 1.903 seconds
So the oscillation can be described by A.sin(ωt) where ω = 2π/T = 3.302
So the maximum angular velocity = ω = 3.302 radians/s.
Hence: T = 2.π.√(0.9/9.81) = 1.903 seconds
So the oscillation can be described by A.sin(ωt) where ω = 2π/T = 3.302
So the maximum angular velocity = ω = 3.302 radians/s.