Maximum Force and Maximum Acceleration
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Maximum Force and Maximum Acceleration

[From: ] [author: ] [Date: 11-11-16] [Hit: ]
So that will go in where f is.On the other side (ma) we know m (.209) and were solving for a.(178 N/m) * (.179 m )=.a = 152.......
A .209 kg mass is attached to a spring with a spring constant at 178 N/m so that the mass is allowed to move on a horizontal frictionless surface. The mass is released from the rest when the spring is compressed .179 m. Find the maximum force on the mass and the maximum acceleration. Thank you.

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Whenever you are given a question that involves forces, you need to think of the equation f=ma

In this question there is only one force, that of the spring (kx). So that will go in where 'f' is.

On the other side (ma) we know m (.209) and we're solving for a.

f = ma
kx = ma
(178 N/m) * (.179 m ) = .209 (a)

solve for a:
a = 152.45 m/s^2

The maximum force is kx
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