If a sample of Mg3(PO4)2, has a mass of 0.200 g, what is the mass of phosphorus in that sample?

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answers:
pisgahchemist say: Mass of phosphorous....

0.200g Mg3(PO4)2 x (1 mol Mg3(PO4)2 / 262.86g Mg3(PO4)2) x (2 mol P / 1 mol Mg3(PO4)2) x (31.0g P / 1 mol P) = 0.0472g P
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say: 0.2 g / 1744.915 g/mol * 2 * 30.97 g/mol = 0.00710 g
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sagcq say: ahdeqaom
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ftdvl say: yywkjbrm
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