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A pure 16.85 sample of the weak base ethyl amine, C2H5NH2, i

## A pure 16.85 sample of the weak base ethyl amine, C2H5NH2, i

[From: Chemistry] [author: ] [Date: 01-07] [Hit: ]
A pure 16.85 sample of the weak base ethyl amine, C2H5NH2, is dissolved in enough distilled water to make 500 mL of solution.?Calculate molar concentration of C2H5NH2......

A pure 16.85 sample of the weak base ethyl amine, C2H5NH2, is dissolved in enough distilled water to make 500 mL of solution.?
Calculate molar concentration of C2H5NH2
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electron1 say: The unit of molar concentration is moles per liter. The first step is to calculate the mass of one mole of ethyl amine.

Mass = 2 * 12 + 5 + 14 + 2 = 45 grams

To determine the number of moles, divide the mass of the sample by this number.

n = 16.85 ÷ 45

The number of moles is approximately 0.374.

Molar concentration = (16.85 ÷ 45) ÷ 0.5

This is approximately 0.748 moles per liter.

I hope this is helpful for you.
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Roger the Mole say: Supposing the missing units on "16.85" to be "grams":

(16.85 g C2H5NH2) / (45.0837 g C2H5NH2/mol) / (0.500 L) = 0.747 mol/L
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