Calculate the approximate molarity (M) of a 13.0% (w/w) solution of H2SO4 (MM = 98.08 g/mol) with specific?

Calculate the approximate molarity (M) of a 13.0% (w/w) solution of H2SO4 (MM = 98.08 g/mol) with specific gravity of 1.090.

A. 2.90 C. 1.44 E. none of the above
B. 2.43 D. 1.22

Start with 1.0L of the solution :
Mass of this 1.0L of solution = 1,090g ( From SG)
Mass of H2SO4 dissolved = 13.0/100*1090 = 141.7g H2SO4
Mol H2SO4 = 141.7/98.08 = 1.44 mol H2SO4 dissolved in 1.0L solution
Molarity = 1.44M - choice C is correct.