Calculate the approximate molarity (M) of a 13.0% (w/w) solution of H2SO4 (MM = 98.08 g/mol) with specific gravity of 1.090.
A. 2.90 C. 1.44 E. none of the above
B. 2.43 D. 1.22
A. 2.90 C. 1.44 E. none of the above
B. 2.43 D. 1.22
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Start with 1.0L of the solution :
Mass of this 1.0L of solution = 1,090g ( From SG)
Mass of H2SO4 dissolved = 13.0/100*1090 = 141.7g H2SO4
Mol H2SO4 = 141.7/98.08 = 1.44 mol H2SO4 dissolved in 1.0L solution
Molarity = 1.44M - choice C is correct.
Mass of this 1.0L of solution = 1,090g ( From SG)
Mass of H2SO4 dissolved = 13.0/100*1090 = 141.7g H2SO4
Mol H2SO4 = 141.7/98.08 = 1.44 mol H2SO4 dissolved in 1.0L solution
Molarity = 1.44M - choice C is correct.