I have four unknowns, and I have to determine which is which by use of indicator only:
0.01M HCl, 0.1M HCl, Distilled Water, 0.1M NaOH
I also have Methyl Orange to tell which one is which.
I know if I add methyl orange to all samples, i'll get two pink (acids) and two yellow (bases).
So from having two acids, a base and water, how can I determine which one is which by possibly mixing them together/using the indicator? Thanks in advance!
____________________________
This is all I can work out.
If I add HCl to the water and the NaOH I should get this:
HCl + H20 ---> H30+ + Cl-
HCl + NaOH ---> NaCl + H20
____________________________
0.01M HCl, 0.1M HCl, Distilled Water, 0.1M NaOH
I also have Methyl Orange to tell which one is which.
I know if I add methyl orange to all samples, i'll get two pink (acids) and two yellow (bases).
So from having two acids, a base and water, how can I determine which one is which by possibly mixing them together/using the indicator? Thanks in advance!
____________________________
This is all I can work out.
If I add HCl to the water and the NaOH I should get this:
HCl + H20 ---> H30+ + Cl-
HCl + NaOH ---> NaCl + H20
____________________________
-
For methyl orange indicator,
Acid -> Red
Neutral -> Orange
Alkali -> Yellow
Try all the 4 sample with Methyl Orange first, see what will happen. You should get
2 Reds->HCl
1 Orange -> Distilled water
1 Yellow -> NaOH
Sometimes, indicator do not show exactly the colour of neutral solution. So you may get Red/Yellow for Distilled water. If you get Red for distilled water, you are lucky, cause NaOH is with you now. If you get Yellow for Distilled water, You need to take another test.
When 2 yellow happens -> Very carefully, put one drop of one of the solutions which show Red into both of the yellows. (Remember to work on new samples) And test it again with methyl orange. Now,one of the Yellow turn to Red, and that is Distilled water. And another will remain Yellow and that is NaOH (cause in limited acid cannot neutralize the solution).
When 3 Red happens -> Very carefully, put one drop of the solution which show yellow into the three solutions. Test it again with methyl orange. You will get 2 Reds and 1 Yellow now. The yellow is Distilled water. And the other 2 solutions are HCl.
The remaining 2 HCl -> carefully pour a same volume of the two solutions which show Red. Add the solution which shows Yellow half the volume of the solutions. Test it with methyl orange. You will get one Red and one Yellow. The Red is 0.1M HCl and Yellow is 0.01M HCl.
Hope this can help you :)
Acid -> Red
Neutral -> Orange
Alkali -> Yellow
Try all the 4 sample with Methyl Orange first, see what will happen. You should get
2 Reds->HCl
1 Orange -> Distilled water
1 Yellow -> NaOH
Sometimes, indicator do not show exactly the colour of neutral solution. So you may get Red/Yellow for Distilled water. If you get Red for distilled water, you are lucky, cause NaOH is with you now. If you get Yellow for Distilled water, You need to take another test.
When 2 yellow happens -> Very carefully, put one drop of one of the solutions which show Red into both of the yellows. (Remember to work on new samples) And test it again with methyl orange. Now,one of the Yellow turn to Red, and that is Distilled water. And another will remain Yellow and that is NaOH (cause in limited acid cannot neutralize the solution).
When 3 Red happens -> Very carefully, put one drop of the solution which show yellow into the three solutions. Test it again with methyl orange. You will get 2 Reds and 1 Yellow now. The yellow is Distilled water. And the other 2 solutions are HCl.
The remaining 2 HCl -> carefully pour a same volume of the two solutions which show Red. Add the solution which shows Yellow half the volume of the solutions. Test it with methyl orange. You will get one Red and one Yellow. The Red is 0.1M HCl and Yellow is 0.01M HCl.
Hope this can help you :)