Consider a sample of calcium carbonate in the form of a cube measuring 2.505 in on each edge.I

If the sample has a density of 2.72 g/cm^3 , how many oxygen atoms does it contain?


Please help me. I'm lost and would appreciate it if someone could explain the answer to me.

Supposing the missing units on "2.505" to be "cm":

(2.505 cm)^3 / (2.72 g/cm^3) / (100.0875 g CaCO3/mol) x
(6.022 x 10^23 molecules/mol) x (3 atoms O / 1 molecule CaCO3) =
7.72 x 10^23 atoms O