I have tried solving this numerous times, and I am still not getting the correct answer. I keep getting 10.1 as my answer which is apparently wrong. Any help would be greatly appreciated!
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10.1. is the correct answer
B + H2O <---> BH^+1 + OH^-1
Kb = [BH+][OH-] / [B]
Let [BH+] = [OH-] = X
Let [B] = 0.18 - X = 0.18 (assume X<<0.18)
9.0x10-8 = X^2 / 0.18
X = 1.27x10^-4
NOTE: assumption was good; 0.18 - 0.000127 = 0.18
pOH = -log(OH-) = 3.90
pH = 14.00-3.90 = 10.10
B + H2O <---> BH^+1 + OH^-1
Kb = [BH+][OH-] / [B]
Let [BH+] = [OH-] = X
Let [B] = 0.18 - X = 0.18 (assume X<<0.18)
9.0x10-8 = X^2 / 0.18
X = 1.27x10^-4
NOTE: assumption was good; 0.18 - 0.000127 = 0.18
pOH = -log(OH-) = 3.90
pH = 14.00-3.90 = 10.10
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Hmm, that's what I keep getting too.
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the Ph is 0.745