1.State which of the following chemical reactions will take place or not, giving suitable reasonfor each.
Zn (s) + Cu SO4 (aq) ----> Zn SO4 (aq) + Cu (s)
Fe (s) + Zn SO4 (aq) ----> Fe SO4 (aq) + Zn (s)
Zn (s) + Fe SO4 (aq) ----> Zn SO4 (aq) + Fe (s)
2.Identify the substance oxidised and reduced in the chemical reaction :
Mn O2 + 4 HCl——>Mn Cl2 + Cl2 +2H2O
3. Why is Plaster of Paris written as CaSo4 • ½ H2O? How is it possible to have
half a water molecule attached to CaSO4?
Zn (s) + Cu SO4 (aq) ----> Zn SO4 (aq) + Cu (s)
Fe (s) + Zn SO4 (aq) ----> Fe SO4 (aq) + Zn (s)
Zn (s) + Fe SO4 (aq) ----> Zn SO4 (aq) + Fe (s)
2.Identify the substance oxidised and reduced in the chemical reaction :
Mn O2 + 4 HCl——>Mn Cl2 + Cl2 +2H2O
3. Why is Plaster of Paris written as CaSo4 • ½ H2O? How is it possible to have
half a water molecule attached to CaSO4?
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1. yes, Zn is more reactive than Cu and will replace Cu
2. no, Fe is not more reactive than Zn
3. yes, Zn is more reactive than Fe and will replace Fe
Mn in MnO2 = 4+ and becomes 2+ in MnCl2.....reduced, gained 2e-
Cl in HCl = 1- and becomes 0 as Cl2.....oxidized, lost 1e-/Cl atom
i guess you could write it as 2CuSO4•H2O but hydrates are written with the salt being 1mole and the water being the one with the coefficient
2. no, Fe is not more reactive than Zn
3. yes, Zn is more reactive than Fe and will replace Fe
Mn in MnO2 = 4+ and becomes 2+ in MnCl2.....reduced, gained 2e-
Cl in HCl = 1- and becomes 0 as Cl2.....oxidized, lost 1e-/Cl atom
i guess you could write it as 2CuSO4•H2O but hydrates are written with the salt being 1mole and the water being the one with the coefficient