This solution was used to determine the concentration of a solution of hydrochloric acid. Four 25.00 mL samples of the acid were titrated with the sodium carbonate solution. The average titration volume required to reach the end point was 23.45 mL.
Hope you can help
Hope you can help
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You need the concentration of the sodium carbonate solution. The reaction is 2HCl + Na2CO3 -----> 2NaCl + H2CO3. From this, one mole of Na2CO3 reacts with 2 moles of HCl If the concentration of Na2CO3 is x M, the moles of Na2CO3 in 23.45 mL is x*0.02345 moles. So there are 2x this many moles of HCl in the 25.00 mL samples. The concentration of the samples is then 2*0.02345*x/0.025 M