A methanol, CH3OH, and water is to be prepared in which the methanol molality of 1.25 m. What is the mole fraction of methanol in this solution?
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The concentration is 1.25 mol CH3OH / 1000 g H2O
? M H2O = 1000 g H2O x 1 mole / 18.0 g = 55.6 mole H2O
Mole graction MeOH = 1.25 mole / 56.9 mole = 0.0220
? M H2O = 1000 g H2O x 1 mole / 18.0 g = 55.6 mole H2O
Mole graction MeOH = 1.25 mole / 56.9 mole = 0.0220