Can you please explain to me how to solve this problem (2xsquared)3rd power
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do you mean (2x^2)^3?
if so then heres your answer:
you just distribute the ^3 into 2 and into x^2
which will make 2^3 times x^6 (you multiply the exponents here)
which gives you a final answer of (2^3)(x^6)
if so then heres your answer:
you just distribute the ^3 into 2 and into x^2
which will make 2^3 times x^6 (you multiply the exponents here)
which gives you a final answer of (2^3)(x^6)
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Thanks for the answers guys they were all good but i looked at seans first
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This expression (2x^2)^3 explains one property of exponents: power of a power. An exponent raised to the power of another exponent, and in this case, you should multiply the two exponents. Ex: (x^2)^2= x^2(2)=x^4
In your problem, don't forget to use the distributive property of multiplication. Distribute the exponent outside the parenthesis to each term inside the parenthesis.
(2x^2)^3
(2^3)(x)^(2)(3)
8x^6
That is the final answer. Hope it helped.
In your problem, don't forget to use the distributive property of multiplication. Distribute the exponent outside the parenthesis to each term inside the parenthesis.
(2x^2)^3
(2^3)(x)^(2)(3)
8x^6
That is the final answer. Hope it helped.
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(2^2)^3
start with the inside of the parentheses:
2^2=4
(4)^3= 64
or you can multiply exponents if they apply to the same base:
2^(2x3)
2^(6)
64
start with the inside of the parentheses:
2^2=4
(4)^3= 64
or you can multiply exponents if they apply to the same base:
2^(2x3)
2^(6)
64
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what do u mean by 3rd power ? is it (1/3)
then (2xsquared)3rd = 2^(2/3)
then (2xsquared)3rd = 2^(2/3)
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(2x^2)^3 = (2 * x * x)^3 = (2*x*x)*(2*x*x)*(2*x*x) = 8*x^6